Požarevac, hotel Dunav, 8-15.12.2025.
U šestom kolu odlučene su četiri partije. Ruski šahista FM Postnikov Artem je savladao kineskog šahistu Liu Huaqi-ja i izdvojio se u vođstvu sa 5 poena. Poen manje imaju velemajstor Branko Damljanović, indijski šahista FM Nagarkatte Vedand i ruski šahista CM Sheremetev Vladislav. Očekuje se uzbudljiv završni dio turnira u kojem čak trojica šahista imaju teoretske šanse za osvajanje IM norme. Ipak, vodećem Postnikovu su potrebna 2 poena iz preostale tri partije, dok su FM Nagarkatteu i CM Sheremetevu potrebne sve tri pobjede što je mala šansa.
| Rezultati 6.kola 2025/12/12 u 16:00 | |||||||||||||
| Bo. | Rtg | White | Result | Black | Rtg | ||||||||
| 1 | 2357 | GM | Damljanovic, Branko | ½ – ½ | Lad, Mandar Pradip | 2392 | |||||||
| 2 | 2325 | IM | Zlatanovic, Boroljub | 1 – 0 | CM | Naveen, Kumar P | 2145 | ||||||
| 3 | 2305 | GM | Lazic, Miroljub | 0 – 1 | CM | Sheremetev, Vladislav | 2194 | ||||||
| 4 | 2264 | FM | Nagarkatte, Vedant | 1 – 0 | FM | Petrovic, Aleksa | 2304 | ||||||
| 5 | 2106 | Liu, Huaqi | 0 – 1 | FM | Postnikov, Artem | 2251 | |||||||
Stanje posle 6.kola
| Rk. | Name | FED | Rtg | Pts. | |
| 1 | FM | Postnikov, Artem | RUS | 2251 | 5 |
| 2 | GM | Damljanovic, Branko | SRB | 2357 | 4 |
| 3 | FM | Nagarkatte, Vedant | IND | 2264 | 4 |
| 4 | CM | Sheremetev, Vladislav | RUS | 2194 | 4 |
| 5 | IM | Zlatanovic, Boroljub | SRB | 2325 | 3 |
| 6 | FM | Petrovic, Aleksa | SRB | 2304 | 3 |
| 7 | Lad, Mandar Pradip | IND | 2392 | 2,5 | |
| 8 | Liu, Huaqi | CHN | 2106 | 2 | |
| 9 | GM | Lazic, Miroljub | SRB | 2305 | 1,5 |
| 10 | CM | Naveen, Kumar P | IND | 2145 | 1 |
Postnikov,Artem (2251) – Naveen,Kumar P (2145)
RUDAR XLVI – IM ROUND ROBIN Pozarevac Hotel Dunav (1), 08.12.2025
1.e4 c5 2.Nf3 Nc6 3.d4 cxd4 4.Nxd4 g6 5.c4 Bg7 6.Be3 Nf6 7.Nc3 0–0 8.Be2 Nxd4 9.Bxd4 d6 10.0–0 Bd7 11.Qd2 Bc6 12.f3 a5 13.b3 Nd7 14.Be3 Rc8 15.Rac1 Nc5 16.Rfd1 f5 17.exf5 Rxf5 18.Nb5 b6 19.Nd4 Rf7 20.Nxc6 Rxc6 21.f4 Rc7 22.Bf3 Kh8 23.Rb1 Qc8 24.g3 Rf8 25.Bg2 Qf5 26.Re1 Rb8 27.Rbd1 Qf6 28.Qe2 Re8 29.Bd4 e5 30.Bb2 Qe7 31.Qd2 Qd8 32.fxe5 Rce7 33.Bc6 Rf8 34.exd6 Ref7 35.d7 Bxb2 36.Qxb2+ Kg8
37.Re8 Nxd7 38.Rxd8 Rxd8 39.Bd5 1–0
Petrovic,Aleksa (2304) – Lad,Mandar Pradip (2392)
RUDAR XLVI – IM ROUND ROBIN Pozarevac Hotel Dunav (3), 10.12.2025
1.d4 Nf6 2.Nf3 d5 3.c4 e6 4.Nc3 dxc4 5.e3 a6 6.Bxc4 b5 7.Be2 Bb7 8.0–0 Nbd7 9.b3 Be7 10.Bb2 0–0 11.Rc1 c5 12.a4 cxd4 13.Nxd4 b4 14.Nb1 Nc5 15.Nd2 Nd5 16.Qc2 Rc8 17.Qb1 Bf6 18.Rfd1 Qe7 19.Bf3 g6 20.Nc4 e5 21.Bxd5 Bxd5 22.Nb6 Be4 23.Nxc8 Rxc8
24.Rxc5 Qxc5 25.Qxe4 exd4 26.g4 Qg5 27.Bxd4 Bxd4 28.exd4 h5 29.d5 Qxg4+ 30.Qxg4 hxg4 31.d6 Rd8 32.d7 a5 33.Rd5 Kf8 34.Rxa5 Rxd7 35.Rb5 Rd4 36.Kg2 Kg7 37.a5 f5 38.a6 Rd6 39.Ra5 Rd8 40.a7 Ra8 41.Kg3 Kf6 42.Kf4 g5+ 43.Ke3 Ke6 44.Kd4 Kd6 45.Kc4 f4 46.Kxb4 Kc6 47.Kc4 Kb6 48.Rb5+ Ka6 49.b4 Rxa7 50.Ra5+ Kb6 51.Rxa7 Kxa7 52.Kd5 Kb6 53.Ke5 Kb5 54.Kf5 g3 55.hxg3 fxg3 56.fxg3 Kxb4 57.Kxg5 Kc5 58.Kf6 1–0
Liu,Huaqi (2106) – Damljanovic,Branko (2357)
RUDAR XLVI – IM ROUND ROBIN Pozarevac Hotel Dunav (5), 11.12.2025
1.g3 e5 2.c4 Nf6 3.Bg2 h6 4.d3 c6 5.Nf3 Bb4+ 6.Bd2 Bxd2+ 7.Qxd2 d6 8.Nc3 0–0 9.0–0 Re8 10.e4 a6 11.b4 Nbd7 12.a4 a5 13.b5 Nc5 14.Rab1 Bd7 15.Rfe1 cxb5 16.cxb5 Bg4 17.Nh4 Be6 18.Qd1 Rc8 19.d4 Ncd7 20.Rc1 Rc4 21.Ne2 Rb4 22.Rb1 Rxb1 23.Qxb1 Nb6 24.d5 Bg4 25.f3 Bd7 26.Qb3
26…g5 27.Nf5 Bxf5 28.exf5 Nbxd5 29.Kh1 Qb6 30.Nc3 Nb4 31.Qd1 d5 32.Qd2 Kg7 33.f4 gxf4 34.gxf4 e4 0–1
Zlatanovic,Boroljub (2325) – Naveen,Kumar P (2145)
RUDAR XLVI – IM ROUND ROBIN Pozarevac Hotel Dunav (6), 12.12.2025
1.f4 c5 2.Nf3 d5 3.e3 Nc6 4.Bb5 Bg4 5.h3 Bxf3 6.Bxc6+ bxc6 7.Qxf3 e6 8.d3 Rb8 9.0–0 Nf6 10.c4 Be7 11.b3 0–0 12.Bb2 Ne8 13.e4 f5 14.e5 Nc7 15.Nc3 Kh8 16.Kh1 Na8 17.Qf2 Nb6 18.Ba3 Nd7 19.Na4 d4 20.g3 g6 21.Qg2 Qc7 22.Rae1 Rg8 23.g4 Rbf8 24.g5 h6 25.gxh6 g5 26.h7 Kxh7 27.Rg1 g4 28.Qe2 Rg6 29.hxg4 Rh6+ 30.Kg2 Bh4 31.g5 Rg8 32.Kf1 Bxe1 33.gxh6 Bg3 34.Bc1 Qd8 35.Qh5 Rg6 36.Ke2 Qg8 37.Qf3 Bh2 38.Rxg6 Qxg6 39.Qxc6 Qg4+ 40.Qf3 Qg1 41.Bd2 Bg3
42.Qb7 Qh2+ 43.Kd1 Bxf4 44.Qxd7+ Kxh6 45.Qxe6+ Kg7 46.Qf6+ Kg8 47.Qg6+ Kh8 48.Bxf4 Qxf4 49.Qh5+ Kg7 50.Qe2 Qg3 51.e6 Kf8 52.Nxc5 f4 53.Qe5 Qg1+ 54.Kc2 Qf2+ 55.Kb1 Qd2 56.Qh8+ Ke7 57.Qg7+ 1–0